That is, as far as I know, a new feature in perl 5.6.0. So first, if you don't have it, you'd better get it. How does it work? Well, this page is all I could find on it (the what's new page).

The example it gives there is this: 

my $a = 10;
my $b = 20;

sub mysub : lvalue {
     if ($_[0] > 0) { return $a } else { return $b }
}
mysub(2)  = 15; # Set $a to 15
mysub(-1) =  9; # Set $b to 9

[download]

Not too tough.

Update:I just noticed it also says "This is still an experimental feature, and may go away in the future; it's also not possible to return array or hash variables yet." so keep that in mind.

72656B636148206C72655020726568746F6E41207473754A

In reply to Re: Subroutine as an lvalue? by reptile
in thread Subroutine as an lvalue? by xeh007

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