And you can inline the if/else using the ? : operators. print $_ % 2 ? "$_ is odd\n" : "$_ is even\n" for (1..5) Results:
1 is odd
2 is even
3 is odd
4 is even
5 is odd

In reply to Re: Checking for odd/even number by perlmonkey
in thread Checking for odd/even number by Anonymous Monk

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