Assuming the test harness provided, I doubt anyone can beat this:

sub f{d,c,b,a,f,e}

[download]

Try this for a test harness:

my @list = (
     a => [ 'b', 'c', 'e' ],
     b => [ 'd' ],
     c => [ 'b', 'd' ],
     f => [ 'a' ],
);
print join (',', map { "'$_'" } f(@list)),"\n";

[download]

Your code produces 'd','b','c','f','e','a', which does not reflect the fact that 'f' depends on 'a'.

So, I am afraid your solution holds only for a limited set of test harnesses -- and is certainly not the shortest among such solutions.

The Sidhekin
print "Just another Perl ${\(trickster and hacker)},"

In reply to Re: Re: Re: (Golf) Dependency List Prioritization by Sidhekin
in thread (Golf) Dependency List Prioritization by tadman

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