SELECT DISTINCT surveys, COUNT(*) col2
FROM neverland
GROUP BY surveys
ORDER BY col2 DESC

[download]
Should work, though it may need an "AS" between the COUNT(*) and the col2 (an alias for the column) depending on the RDBMS (I don't know much about MySQL I'm afraid).

In reply to Re: ORDER BY COUNT(*)? by Matts
in thread ORDER BY COUNT(*)? by peppiv

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