Block-chain ciphers are (IIRC) always on 8-byte boundaries. This means that if the input text is not an even multipe-of-8 bytes in length, it gets padded in such a way that the decryption stage knows to discard the padding.

That having been said, your input string is 26 bytes long. Padding to an 8-byte boundary would yield a block of 32 bytes. I'm not sure why you are taking the length and multiplying it by two, except that you are displaying hexadecimal and may be under the impression that the hex value "aa" requires two bytes simply because it is two characters when printed-- it's still one byte (decimal value 170, in fact).

--rjray

In reply to Re: Length of Crypt::CBC result by rjray
in thread Length of Crypt::CBC result by talexb

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