> Keep in mind that perl currently doesn't do nested subs
Ack, how un-DWIM! 
sub foo {
    my $x = "a var in foo()";
    sub bar {
        print "\$x is - [$x]\n";
    }
}
bar();

__output__

$x is - []

[download]
But if we use a closure, all is well with the scope of $x 
sub foo {
    my $x = "a var in foo()";
    return sub {
        print "\$x is - [$x]\n";
    }
}
foo()->();

__output__

$x is - [a var in foo()]

[download]
I was vaguely aware of the fact that nested subs in perl were broken (i.e scoped to current package, not current sub) and now I know the full extent (but I guess the logic should've followed really). Oh well, not much longer til Perl6 anyway ...
HTH

broquaint

In reply to Re: Re: Scoping issue when sorting with subroutines by broquaint
in thread Scoping issue when sorting with subroutines by Dave05

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