First off, why are you doing two sorts? Sorts are pretty damn expensive (or so I'm told). Especially in this case, I would imagine, since hash lookups on anagrams (act, atc, cat, cta, tat, tca) are particularly slow. Being timestamps they are restricted to a 10 character set, and most likely be all of the same length, thusly ensuring that a portion of a decent sized will be anagrams.
($j, $l) = (sort keys %master)[0,-1];
Second
#Might go with a C-style for-loop here. while($j <= $l){ for my $elem (qw(CCMT ...)){ $out .= "," . ($master{$j}{$elem} || '0'); } $j+=60; }

--
perl -pe "s/\b;([mnst])/'\1/mg"


In reply to Re: Golf, Anyone? Stupid output questions by belg4mit
in thread Golf, Anyone? Stupid output questions by Anonymous Monk

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