well, this looks simple. i haven't run it, but it looks like it will work if %$p and %$q implement exactly the same keys. my example works on the intersection of keys between %foo and %bar (only the keys both hashes share.) perhaps i solved a more general problem than the original poster requested.

question: what happens to your code if a key exists in %p2q, but not in %$p? my code will not auto-vivify a key in %$q. will yours?

by the way, values and keys are guaranteed to output in the same order (in the same hash.) this is by no means guaranteed in different hashes. see each for a little detail.

~Particle ;Þ

In reply to Re: Re^2: Bulk Hash Assignment by particle
in thread Bulk Hash Assignment by tadman

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