In the above example, we evaluate the expression right to left.

Is that always, or just in this case? When are expressions evaluated left-to-right, and when right-to-left? And why is that so? I would have thought that do { $i = 0; ++$i + $i++; } would evaluate to 2 because (0 + 1) + 1 == 2, but apparently, I'm wrong.

Update: Got the concept right, but I evaluated in reverse order. Whoops! Juerd is right.

Answer to Ovid's update: No, I'm not, as do { $i = 0; ++$i + $i++ } does NOT equal 2 -- the right-to-left apparently is correct, I'm just wondering why it is that way. 

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In reply to Re: Re: $i=$i++ by Juerd
in thread $i=$i++ by Anonymous Monk

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