s/foo/bar/ is not just a regular expression, it's a substitution operator. Storing it in a scalar and expecting it to work is going to be just as effective as storing $foo = "2+2" and expecing $bar = $foo to set $bar to 4. You want to

In reply to Re: Storing Regular Expressions as Strings in Array?? by Fletch
in thread Storing Regular Expressions as Strings in Array?? by arunhorne

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