Perhaps you need to use my $myhashname=$_; instead of my $myhashname=$;
Your programming style is very different to mine, but if you try to tell us what you method intends to do, it will be possible to give you some working code.
However if you are getting "cannot open file" then $myhashname cannot be a valid filename. Perhaps try putting print $myhashname above the open command to check the filename being passed or use the debugger to find this. Finally, its not clear from your code if you are trying to read from or write to the the file, if you want to write to it your open statement should look this this:
unless (cpen (FH, ">$myhashname")) {Hope some of this helps, post back with more info if it doesn't.
Arun
In reply to Re: How to open sub FH when filename is passed to sub?
by arunhorne
in thread How to open sub FH when filename is passed to sub?
by Anonymous Monk
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