Thats interesting - I was under the impression brackets were used as a memory more than a precedence operator... do they provide precedence in the conventional sense of the word and therefore why does this not work...

m/(\S=\S)|( =\S)|(\S= )/g

... to look for all the occurences of an equals sign that is not got whitespace on either side?

Thanks.

In reply to Re: Re: Using OR () in Regex by arunhorne
in thread Using OR () in Regex by arunhorne

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