How about this for brute force? 
my @new;
my $count = 4; # by this many
for (my $i = 0; $i <= $#old; $i++) {
  $new[$i / $count][$i % $count] = $old[$i];
}

[download]

-- Randal L. Schwartz, Perl hacker

In reply to Re: list to LoL by merlyn
in thread list to LoL by princepawn

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