I think perl's clobbering or removing backreferences somewhere, and you're trying to access \1 after perl's done something else with it.
If $1 is assigned to a temp var within dofunc, the code no longer dumps core. Below is my test, and output...
#!/usr/bin/perl -w
use strict;
my $weeping;
print doFunc( "AABBCC",0 );
print doFunc( "AAAABBBBCCCC",0 );
sub doFunc {
my( $theParam,$depth) = @_;
print STDERR "\ndofunc($theParam)\n";
my $re;
$re = ${['(.+)$weeping']}[$depth]||'(.+)($weeping)';
print STDERR join"\n", $theParam =~ /$re/g,undef;
$theParam =~ s/$re/&doFunc($weeping,$depth+1)/ge;
$weeping=$1;
++$theParam;
print STDERR "=$theParam\n";
return $theParam;
}
and this gives us
dofunc(AABBCC)
=AABBCD
AABBCD
dofunc(AAAABBBBCCCC)
=AAAABBBBCCCD
AAAABBBBCCCD
Now, if you'll excuse me, I need to go wash my hands compulsively :-)
update so what output do you expect, out of curiosity?
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