Another solution for the hell of it. No idea how you would coax the second solution out of it. No matter how I tweak things (shotgun debugging :) it converges to the same answer. Hmm.
#!/usr/bin/perl
use strict;
use warnings;
my @arr = (0..9);
my %hash;
@hash{@arr} = (0) x @arr;
sub scanit
{
my $number = shift;
my $cnt = 0;
for (0..9)
{
foreach my $c (split //, $hash{$_})
{
$cnt++ if ($number == $c);
}
}
$cnt+1;
}
my $solcount=0;
while (1)
{
my $cond = 0;
# update the counts
for (my $i=9; $i>=0; $i--)
{
my $cnt = scanit($i);
$hash{$i} = $cnt;
}
# check whether our solution is valid.
for (0..9)
{
my $cnt = scanit($_);
$cond = 1 if ($hash{$_} != $cnt);
}
# print it if it is.
if ($cond == 0)
{
my @print;
for (1..9)
{
push @print, "of $_ "."s is $hash{$_}";
}
print "The number of 0s in this sentence is $hash{0}, " .
join(", ", @print) . "\n";
die;
}
else
{
$cond = 1;
}
}
--
Ash OS durbatulk, ash OS gimbatul,
Ash OS thrakatulk, agh burzum-ishi krimpatul!
Uzg-Microsoft-ishi amal fauthut burguuli.
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