That's not very hard. The fact your other two programs are Perl programs is irrelevant. Let's call them program1 and program2.

We need to do two things. First call the first program, and collect its exit value, then use the exit value as a parameter to the second program. To call an external program and collect the exit value, we use the system function. Note what perldoc -f system has to say:

 
    The return value is the exit status of the program as returned by
    the "wait" call.  To get the actual exit value divide by 256.
    ...
    Return value of -1 indicates a failure to start the program (inspect
    $! for the reason)
So, start off with this code fragment:
my $exit1 = system "program1"; if ($exit1 == -1) { die "Failed to call 'program1': $!\n"; } $exit1 >>= 8; # Get the real-exit value. The bits we # are shifting off are any possible signals.

And now we can call the second program. Any additional arguments to system will be arguments to the called program. We get:

my $exit2 = system "program2", $exit1; if ($exit2 == -1) { die "Failed to call 'program2': $!\n"; }

Abigail


In reply to Re: How to get value from one Perl program to another? by Abigail-II
in thread How to get value from one Perl program to another? by sachinb

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