Wherefore does the following code work?
  
@l = 0..10;
%h = (a => 1, b => 2);

print @l->[4]; # prints 4
print %h->{b}; # prints 2

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My reading of perlop has me convinced that this is an unintended syntactic feature. 
   MeowChow                                   
               s aamecha.s a..a\u$&owag.print

In reply to Arrow Operator Oddment by MeowChow

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