Thank you all for the past responses, but all solutions have failed. Partly because I did not explain clearly enough. This is a tough one. The problem: 
a file shows up in /main, it needs to move to /dir1
another file shows up in /main, it moves to /dir2
ditto for /dir3 through /dir6
then we need to start again at /dir1
a round-robbin approach to file distribution.

[download]
Now here is the seemingly impossible parts: say there are two files in main and the last time the program ran, it had moved a file to /dir2, it now needs to put one file in /dir3 and the other in /dir4. (date/time stamp of files is no issue as this will be a cron job or it will sleep and run every 5 minutes) Say this program runs again and there is a file in /main, it now needs to start at /dir5. And as if this isn't bad enough, if there is no file there, it needs to remember the last /dir# it was at and pick up from there! aaargh! I'm thinking the program can read a file with all the /dir#'s into an array, shift them somehow and white back out to the file. Do a substr to take out the valid /dir# then FORMAT a executable sh file with 'mv /main @<<<<<<' type thing. Assuming this is not impossible, Thanks for any code help I can get!

In reply to sequential file handling (yet again) by Anonymous Monk

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