Using hashes is one way to tackle the problem, as others have shown.
But since your example suggests that the data is clumped - that is,
numbers which are the same follow each other, you don't need a hash,
as the program below shows.
I'm just showing it here for the sake of showing an alternative way.
I don't expect it to be faster - hashes are pretty fast, and the sort
is likely to dominate the running time anyway.
Abigail
#!/usr/bin/perl
use strict;
use warnings 'all';
my @info;
while (<DATA>) {
my ($num, $info) = split ' ', $_, 2;
if (@info && $num == $info [-1] [0]) {
$info [-1] [2] ++;
}
else {
push @info => [$num, $info, 1]
}
}
print map {"@{$_}[0, 1]"} sort {$b -> [2] <=> $a -> [2]} @info;
__DATA__
1 info1
1 info1
1 info1
2 info2
3 info3
3 info3
4 info4
4 info4
4 info4
4 info4
$ ./count
4 info4
1 info1
3 info3
2 info2
$
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