Something else to consider: "distribution" (or lack thereof) of the binding operator. Note that
$_ =~ (/A/ && /B/) is not equivalent to
($_ =~ /A/) && ($_ =~ /B/).
The latter is what you would want.
Regarding the original poster's code:
$count++ if $_ =~ /\b$dst[0]\b/ && /\b$service[
+0]\b/;
This works only because $_ is being tested. Taking precedence into consideration (and the fact that m// works on $_ by default), this code is equivalent to
($_ =~ /\b$dst[0]\b/) && ($_ =~ /\b$service[+0]\b/);
If the data were in any other variable ($var, for example), and one just replaced $_ with $var in the OP's code, it would be equivalent to
($var =~ /\b$dst[0]\b/) && ($_ =~ /\b$service[+0]\b/);
which isn't What You Want.
Just my observations. HTH.
--
There are 10 kinds of people -- those that understand binary, and those that don't.
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