The reason that your script works is that it isn't really changing the array. You're appending an empty set to it.

If there were one or more values after the array name in the unshift call, the script would print "1", then consume all available memory before doing anything else.

update: I should have said "you're not prepending anything to the array.

Also, the script might print more things before running out of memory, if you happen to prepend more than one element at a time, and the second element of that set was not "2" or "4". But the script will still blow up.


In reply to Re: walking an array and unshifting by graff
in thread walking an array and unshifting by smackdab

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