$_=param('nameoffile'); tr/a-z//cd; print ">$_"; if (!(open (OUT, ">$_"))) { print "Error opening file $_ for writing."; exit 0; } why are you using $_ to store a file name anyway ?? try using a declared variable for storing the file name that will work

In reply to RE: Opening a file error by rendhalver
in thread Opening a file error by Anonymous Monk

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