if one can't deprototype the target function...

If all you want to do is disable the prototype, then calling the function with & will do it --- beware that @_ is passed implicitly if you leave off the parens, and you'll have to adjust your argument passing for more complex prototypes (such as: (&@) or (\@)) to ensure the function gets what it is expecting.

In reply to Re: Re^N+1: Function Prototypes and Array vs. List (Pt. 2) by danger
in thread Function Prototypes and Array vs. List (Pt. 2) by tadman

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