No, all you need to know is how => works. You have the same problem in: 
#!/usr/bin/perl

use strict;
use warnings 'all';

sub foo {
    my %hash = (shift => 1);
    print keys %hash, "\n";
}

foo "bar";

__END__

[download]
That prints shift and not bar.

Abigail

In reply to Re: Behavior of compile-time constants? by Abigail-II
in thread Behavior of compile-time constants? by laughingboy

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