Hi,
Sorry, but this is not exact. Doing 

my ($a,$b) = @_;

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you do not drop anything. Just try this: 
sub test1 {
  my ($a) = @_;
  print "\$a = $a\n";
  print "\@_= (",join(",",@_),")\n";
}
sub test2 {
  my $a = shift;
  print "\$a = $a\n";
  print "\@_= (",join(",",@_),")\n";
}

test1(1,2,3,4,5,6,7);
test2(1,2,3,4,5,6,7);

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the call to <emph>test1</emph> prints 
$a = 1
@_= (1,2,3,4,5,6,7)

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while the one to <emph>test2</emph> prints: 
$a = 1
@_= (2,3,4,5,6,7)

[download]

The basic difference should be obvious from the above examples: assigning @_ does not modify @_ (that is obviously consistent with standard assigement semantics), while using shift physically modify @_ </>

Cheers

Leo TheHobbit

In reply to Re: Re: Getting parameters in subs by TheHobbit
in thread Getting parameters in subs by BrowserUk

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