Just the other night I came across the following. Consider
use strict;
use warnings;
my %foo;
@foo{1..3} = ();
print keys %foo;
@foo{qw/1 2 3/} = ();
print keys %foo;
both ways to assign to a hash slice work fine and produce the
same results as expected.
Now add the following line to it:die "strange .." if foo eq 'bar';
which should make perl barf a "use of bareword 'foo' " error
- as we are under strict. But it doesn't!! At least for
me. I tried this under Perl 5.6.0 (ActivePerl Build 623) on
Windows and Perl 5.6.1 on Linux (2.2.14).
If you remove the first hash slice line
(@foo{1..3} = ();) then it works (or better not
works i.e. throws the bareword error) correctly.
Well, so my questions are:
- can anyone reproduce that behaviour (on different versions)?
- can anyone explain it?
- is it a (known?) bug?
-- Hofmator
2002-06-23 Edit by Corion : Changed title
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