You need to pass it by reference like so 
sub take_subs {
    $_->() for @_;
}

sub foo { print "in foo()\n" }
sub bar { print "in bar()\n" }

take_subs(\&foo, \&bar);
#         ^^     ^^

__output__

in foo()
in bar()

[download]
See the perlsub and perlref manpages for more details.
HTH

_________
broquaint

In reply to Re: subs as args by broquaint
in thread subs as args by Anonymous Monk

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