You're going to have to do an eval on the $rpl text in order to get it to evaluate the $1 within the regex.

Update Well, I thought doing a s///e on it would be the ticket, but apparently not. I'll keep working on it though. :-)

Update: The following code will work, you just have to change your placeholder from $1 to %s. 

#!/usr/bin/perl -w
use strict;

my $find = 'proof(\S+)';
my $rpl  = 'read%s';
my $text = 'proofing is proof it needed to be proofed';

if ($text =~ s/$find/ sprintf($rpl,$1) /e) {
    print "1st replacement made:\n\t$text\n";
}

[download]
Yes, it does place some limitations depending on how you are going to use it, but that's life. :-)

-caedes

In reply to Re: evaluating $1 in a replace string by caedes
in thread evaluating $1 in a replace string by Oaks

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