Regarding: Well, I thought doing a s//e on it would be the ticket, but apparently not.

It takes a little extra work, but it is certainly do-able... 

#!/usr/bin/perl -w
use strict;

my $find = 'proof(\S+)';
my $rpl  = '"read$1"';
my $text = 'proofing is proof it needed to be proofed';

if ($text =~ s/$find/$rpl/ee) {
    print "1st replacement made:\n\t$text\n";
}

[download]
The double /ee is needed. The first /e sub's in the value of $rpl. The second /e evaluates that and DWIM's.

The nested quotes are needed in defining $rpl because without the inner double-quotes, the second /e fails. Another way to do that bit (and this may help in understanding) would be: my $rpl  = '"read" . $1'; You have to get both the quoting and the /ee right for the thing to work as intended.

HTH

------------------------------------------------------------
"Perl is a mess and that's good because the
problem space is also a mess." - Larry Wall

In reply to Re: Re: evaluating $1 in a replace string by dvergin
in thread evaluating $1 in a replace string by Oaks

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