The variable $hex_num doesn't "know" that the number is in hex, just that it's an integer. Your code as written is actually equivalent to this:
$hex_num = 3914;
print $hex_num;

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What you might want is this:

$hex_num = 0xf4a;
printf "0x%x", $hex_num;

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In reply to Re: Output numbers in hex by seattlejohn
in thread Output numbers in hex by Anonymous Monk

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