Background: If you call the value of a segment of memory,
I'm thinking C/C++ here, then the value returned is the
value that already exitst in that memory space. For example:
if 12345 existed at a specific segment of memory that was
then assigned to $var, the value of $var would be 12345.
Unless you predeclare that $var is to be a specific value
That is a well known security problem, I believe that is
how stack exploites work.

Abigail says that the variable is assigned an empty list
either way you choose to assign it (my $var or my $var = ()).

If that is true then there should be no security differences
between either way. Sound correct?

In reply to Re: Predeclaration by cybear
in thread Predeclaration by hakkr

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