for($i=2; $a <= 7; $a++) {
  if($slog[$i]) {
    $a = $i + 5;
    print "$slog[$i] $slog[$a]";
  }
}

[download]
I dont get this, I have more than one, there info in $slog3 its just printing $slog2 and $slog7

In reply to for only returning one result by Anonymous Monk

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