30 chars:
sub hexout4 {
"@{[unpack('H*',pop)=~/../g]}"
}
On a related note does anyone know why the
sprintf format "%#x" behaves differently for 0 than for other numbers.
printf "%#x\n", 0;
printf "%#x\n", 1;
__END__
Prints:
0
0x1
I guess that the behaviour comes from the C compiler that builds perl because the following gives the same results (at least where I could test it):
int main () {
printf("%#x\n", 0);
printf("%#x\n", 1);
return 0;
}
So why is 0 treated differently?
--
John.
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