First of all, sorry about the additional post; refreshing the page on my browser had that unfortunate side effect. However, disregarding where I put the result, suppose I changed it to : 
#!/usr/bin/perl
$a = 10;
$result = ($a+=5) + ($a-=10);
print "$result";

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My question is, since the assignment is made to the scalar variable $a using += and -= at supposedly different times, which parentheses is evaluated first? Or are they evaluated at the same time? I know there are different ways to do this; this is a kind of "What is the philosophy of Perl on this situation?" type of question, because I was curious. The possible answers I can see are:
1: parenthesis right to left: (0+5)+(10-10) = 5.
2: parenthesis left to right: (10+5)+(15-10) = 20.
3: parenthesis simultaneously: (10+5)+(10-10) = 15.
However, when this is run, with the modifications above, I still get 10 as an answer.

In reply to Re: Re: precedence question by Anonymous Monk
in thread precedence question by Anonymous Monk

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