Fellow monks,

I'm doing a conversion of some pascal code of a friend's to Perl to convince him to learn Perl. And after seeing his 8 pages of code I was sorely convinced I could do it in no more than 2 in Perl and still make it non-obsfu. :)

Given the following code in pascal: 

function roll(point : integer) : real;
begin
   case point of
     2,12: roll := 1/36;
     3,11: roll := 2/36;
     4,10: roll := 3/36;
     5,9: roll := 4/36;
     6,8: roll := 5/36;
     7: roll := 6/36;
   else
       writeln('invalid roll');
       roll := 0;
   end; { case }
end; { rolls }

[download]

This is what I've converted it to in Perl: 

sub roll{
         my $i = shift;
         my %roll=( 2=>1, 3=>2,4=>3, 5=>4, 6=>5, 7=>6,
                    8=>5, 9=>4, 10=>3, 11=>2, 12=>1);
         $i = $roll{$i}/36;
         return $i;
    }

[download]

What I'm curious about is this: Is there a way to do this cleaner or more efficiently? At first I thought tr was the way to go until I realized it was only going to work for 2-9, and once you hit 10-12 you were stuck.

I also thought about the array approach using just the indicies 2-12 but the hash just lays it out so well.

Any ideas would be greatly appreciated!

Some people fall from grace. I prefer a running start...

In reply to Converting pascal code to perl by Popcorn Dave

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