it is quite clear that $1 qnd $2 are not displayed the same (since the regex are different...) but u might want to use : 
while(<>){
        print if m!(\d+)\D*to\D*(\d+)!i;
        print "$1\n";
        print "$2\n";
}

[download]
i hope i got your question right ...

----
NaSe
:x

In reply to Re: $1 and regex by NaSe77
in thread $1 and regex by Anonymous Monk

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