Actually this is more complicated than a pure regex can handle (perl regexes _may_ be able to handle this, but the code would be scaaaary), this problem is even more difficult than handling balanced constructs and cannot be solved using a formal regular expression.
This is because we cant simply look for .{BS}, as is clear from your sample data such as bnack{BS}{BS}{BS}{BS} where the last {BS} actually remove the 'n'.
But only a slight amount of additional code will allow a working solution....
my $logdata=<<EOLOG;
pass{BS}{BS}{BS}{BS}{BS}{BS}
hee{BS}llo, I'll be bnack{BS}{BS}{BS}{BS}ack next saturday.{BS}{BS}{BS
+}{BS}{BS}{BS}{BS}{BS}{BS}{BS}{BS}{BS}
www.yahoo.com "keyloggers" + "linux"{BS}{BS}{BS}
EOLOG
my $clean;
while ($logdata=~/\G(\{BS}|.)/sg) {
length ($1)>1 && (length($clean)==0 || substr($clean,length($clean
+)-1,1,""))
or $clean.=$1;
}
print $clean;
YMMV
Yves / DeMerphq
---
Software Engineering is Programming when you can't. -- E. W. Dijkstra (RIP)
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