"...that Delta_YMD returns the vector [y2 - y1], [m2 - m1], [d2 - d1]."

Thank for the ClueBy4. Read it a few times, just didn't register clearly. I guess I took "Delta" to be a little bit more literal than plain ole subtraction.

Many thanks for the code snippet. Time to study it for a while.

In reply to Re: Re: Date::Calc / Delta_YMD funkyness? by jk2addict
in thread Date::Calc / Delta_YMD funkyness? by jk2addict

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