I see where I missed part of your specification. Here is try number 2. Now, the thing to note here is that my output is slightly different than the one you posted above. The "whatever = something" pairs are moved around a little bit. If I remember my SQL syntax, I don't believe it should matter too much. Let me know if it does, and I can help you fix it. Anyhow, here is the new updated code:

%hash = ( "view0" => [qw/buffersize size value speed/], "view1" => [qw/buffersize size value speed/], "view2" => [qw/buffersize size value speed/], "view3" => [qw/buffersize size value speed/]); my $lastview; my $output; foreach $key (sort(keys %hash)){ # Do this only the first time. if(not defined($lastview)){ $lastview = $key; $output = "$key"; next; } $output .= " full outer join $key on "; my $i; $array_elements_used = scalar(@{ $hash{$key} })-1; #loop through all of the elements except for the last for($i=0;$i<$array_elements_used;$i++){ $output .= "$lastview.$hash{$lastview}[$i] = $key.$hash{$key}[$i]" +; # only add an "and" if this is not the last element used. $output .= " and " if ($i != ($array_elements_used-1)); } $lastview = $key; } print $output, "\n"; ============= output: view0 full outer join view1 on view0.buffersize = view1.buffersize and + view0.size = view1.size and view0.value = view1.value full outer joi +n view2 on view1.buffersize = view2.buffersize and view1.size = view2 +.size and view1.value = view2.value full outer join view3 on view2.bu +ffersize = view3.buffersize and view2.size = view3.size and view2.val +ue = view3.value

In reply to Re: Re: Re: Using hash elements to create a string by RollyGuy
in thread Using hash elements to create a string by johnirl

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