Hey Monks
With regard to this question my current effort is this which is unforunatly still not working. I am sure I am missing something elementrary and would appreciate it if someone could point it out to me.
Thanks 

#!/usr/bin/perl

use strict;

my @views = ( 'view0', 'view1');
my $num_of_views = scalar(@views);
my %hash;
my @global_include = ("size, buffersize, value", "size, buffersize, va
+lue");
my $lastview;
my $output;

for (my $j = 0; $j < $num_of_views; $j++){
   my @array = split (", ",$global_include[$j]);
   pop @array;
   $hash{$j} = \@array;
}

#for (my $j = 0; $j < $num_of_views; $j++){
#   my $ref = $hash{$j};
#   print "HASH CONTAINS FOR $j: ";
#   foreach (@$ref){
#        print "$_\n";
#   }
#}

foreach my $key (sort(keys %hash)){
    # Do this only the first time.
    if(not defined($lastview)){
    $lastview = $key;
    $output = "$key";
    next;
    }

    $output .= " full outer join $key on ";
    my $i;
    my $array_elements_used = scalar(@{ $hash{$key} })-1;
    #loop through all of the elements except for the last
    for($i=0;$i<$array_elements_used;$i++){
    $output .= "$lastview.$hash{$lastview}[$i] = $key.$hash{$key}[$i]"
+;
    # only add an "and" if this is not the last element used.
    $output .= " and " if ($i != ($array_elements_used-1));
    }
    $lastview = $key;
}
print $output, "\n";

[download]

j o h n i r l .

Sum day soon I'Il lern how 2 spelI (nad tYpe)

In reply to Using hash elements to create an SQL Statemant by johnirl

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