dmitri said:
$linenum = &{sub{(caller)[2]}};
blakem said:
$linenum = __LINE__;

dmitri's solution returns the line number of the call tothe line in the current subroutine.

blakem's solution returns the line number of the __LINE__ within the current subroutine.

Amended 4:10p PDT I'm not sure why dmitri is building a subroutine reference only to call it. dmitri, do you care to clarify?

At 4:15, after reading blakem's follow-up, I realize blakem is right. dmitri's would be different, if he'd said:

$linenum = (caller)[2];
but he didn't. So they are equivalent, and I must say that __LINE__ is much simpler.

In reply to Re: Re2: line number by jkahn
in thread line number by Jaap

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