That wouldn't make much sense, because a character class can match any of its characters, but how should it be interpreted in the right side of s///? Should that mean all the characters it represents? Or a random one?
The following code does what you want:
Now let me explain your errors:for (@links1) { s/<\s*a\s.*?\b(href\s*=\s*".*?").*?>/<a $1>/i; }
@links1=~ # that would work like scalar(@array)=~ s/ .* # replace complete string with / href # 'href' \s* # as many spacey chars as possible \= # no need to escape '=' \s* # as many spacey chars as possible \" # no need to escape '"' .*? # as few as possible (=no) anythings \" # no need to escape '"' /isx; # 's' is not needed, I added 'x'
~Django
"Why don't we ever challenge the spherical earth theory?"
In reply to Re: Re: Re: Re: Re: Substitution Problem
by Django
in thread Substitution Problem
by Wassercrats
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