Can you explain a few things I don't understand?

- First thing I don't understand is this way of making
subs (sub'i, sub'p, sub'f) what's the main difference
from the sub i{..}.

- Second, in this line : \;$m.="$/$/$/$/$/$/1; I don't
really get what you are doing there.

- Third, $/$/$/$/$/$/$/";; why ;;?

#!/usr/bin/perl


$m=q\$g=59;
$s=23;

@v=($",$",'.',';','x','X','M');
$t=[map{[(split('',$_))[0..$g]]}reverse+split($/,$m)];

sub'i{
    ($b)=@_;
    $b->[0]=[(0)x($g+1)];

    for(@{$b->[0]}){
        $_=$#v*(int(rand(7))<3);
    }

    for(1..($s)){
        @{$b}[$_]=[(0)x($g+1)];
    }
}
sub'p{
    ($b)=@_;
    system($^O=~/MSWin32/ ? 'cls': 'clear');

    $str='';
    for $r(reverse(0..$s)){
        for $c(0..$g){
            $str.=($t->[$r][$c]eq$"?$":@v[int $b->[$r][$c]]);
        }$str.=$/;
    }
    print $str;
}

sub'f{
    ($x)=@_;$b=[];i($b);

    for $r(1..($s-1)){
        for$c(1..($g-1)){if(int(rand(2))){
             $v=0;for$ri(-1..1){
             for$ci(-1..1){
                   $v+=$x->[$r+$ri][$c+$ci];
             }
        }

         $b->[$r][$c]=$v/9;
    }else{

    $b->[$r][$c]=$x->[$r-1][$c];}}}
    return $b;

}

$z=[];
i($z);
p($z);
while(1){
    $z=f($z);
    p($z);
}

\;$m.="$/$/$/$/$/$/1;
$/$/$/$/$/$/$/";;
s//$m/;
s/$"//g;
s|$/||g;
eval

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In reply to Re: PM Obfu by husoft
in thread PM Obfu by Felonious

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