You say it's "a reference to a scalar", but don't you mean to say it's a reference to a code reference? You can add as many backslashes as you like, you only have to dereference them sufficiently to get at the underlying referent.
I think I understand, but I'm a bit puzzled by your terminology. Seems like a cool trick to me, let me see if I understand you correctly:
#! /usr/bin/perl -w
use strict;
sub foo { "this is foo" }
sub bar { "this is bar" }
my @later;
sub do_it {
my $ref = shift;
if( ref($ref) eq 'CODE' ) {
print "do it now: ", $ref->(), "\n";
}
elsif( ref($$ref) eq 'CODE' ) {
push @later, $$ref;
}
}
do_it( \&foo );
do_it( \\&bar );
print "deferred ", $_->(), "\n" for @later;
Is that what you mean? If so, yeah, I like it.
print@_{sort keys %_},$/if%_=split//,'= & *a?b:e\f/h^h!j+n,o@o;r$s-t%t#u'
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