The question is: do you know how to do it "by hand"? Here's my process (the number that you want to convert is n):
  1. Find the largest k such that 2k ≤ n. Your binary number k+1 digits, starting with a 1
  2. Subtract 2k from your n.
  3. Subtract 1 from k.
  4. If 2k is larger than n, put a 0 down in your binary number. If k is smaller or equal to n, place a 1 in your binary number, and subtract 2k from n.
  5. redo the previous step until k is 0.
Now, here's a simple example for n=10:
  1. 20 = 1 ≤ 10,
    21 = 2 ≤ 10,
    22 = 4 ≤ 10,
    23 = 8 ≤ 10,
    24 = 16 > 10.
    Thus, k=3, and our binary digit will have 4 bits, starting with a 1.
  2. n=10-23=2,
    k=3-1=2
  3. 22 = 4 > 2, so we put a 0.
    k=2-1=1
  4. 21 = 2 ≤ 2, so we put a 1.
    k=1-1=0,
    n=2-21=0
  5. 20 = 1 > 0, so we put a 0.
  6. So, our net result is 1010
From this, you should be able to code your algorithm. A for loop comes to mind...;)

thor

In reply to Re: Base10 to Base2. by thor
in thread Base10 to Base2. by Anonymous Monk

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