ls | perl -lne '$o = $_; s/DOTX/DOT_TEST/; $n = $_; warn "***$o, $n"'

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However, $o and $n are both the same. I want to do a rename($o, $n) but it won't work if both variables are the same. So it seems that a reference is being made to $_instead of a copy being put in $o.

Any idea why?

In reply to [perlrun; perlre] $_ seems aliased instead of copied in assignment... why? by princepawn

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