And my 2 cents worth..
A function prototyped to accept no arguments is treated as a candidate for inlining by the Perl compiler. In this case sub foo(){2} will be inlined because it returns a constant. The snippet will thus print 2, because print foo(); is turned into print 2; by the compiler, no matter what you do to the definition of sub foo later on at runtime.
Nice one, Ovid!

CU
Robartes-

In reply to Re: Little Perl Mysteries: what's your answer? by robartes
in thread Little Perl Mysteries: what's your answer? by Ovid

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