Logically they are the same

Unfortunately not. routine1 makes the assignment without modifying @_, whereas routine2 consumes elements of @_. Add something like return $_[0]; to each of the above and in general you will get different results...

        $perlmonks{seattlejohn} = 'John Clyman';

In reply to Re: Re: Argument Passing, preference or performance ? by seattlejohn
in thread Argument Passing, preference or performance ? by the_Don

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