'perldoc -f scalar' unhelpfully tells me:
There is no equivalent operator to force an
expression to be interpolated in list context 
because in practice, this is never needed.  If you
really wanted to do so, however, you could use the
construction "@{[ (some expression) ]}", but usually
a simple "(some expression)" suffices.

[download]
I want to use a scalar $string in a very C-like way,
that is I want to run through the @string character
by character, fiddling with chars along the way.
I've tried the above suggestion, as well as:
foo( () = bar() );

[download]
but I can't see how either syntax can be used. Any suggestions?

Before you ask why I don't just do this in C, it's because I want
to see if it can be done in Perl.
So there!
--
Microsoft delendum est.

In reply to Forcing array context by jens

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