I'm trying out the transliteration operator with normally non-printing octet values largely to understand who it works. On it's fact it's just non-intuitive and I'm asking for help here. You'll notice from both of these cases that the transliteration patterns are both of the same format - three characters with three other characters using the /c invert and /d delete modifiers. The first example behaves normally while the second does an odd thing before hitting the expected patterns.

So can someone explain what I'm doing wrong here or where the bug is? I don't even know which should be the expected behavior. I get these results on OpenBSD perl 5.6.1, W2K ActiveState perl 5.6.1 build 633 and W2K Cygwin perl 5.8.0. I'm using this without unicode so I'm specifically referring to "character" as "octet" to avoid confusion.

$_ = "1234567890";
tr [357]
   [888]cd;
print $_, $/;
# prints 357

$_ = join '', map chr(), 0 .. 0x1f;
tr [\3\5\7]
   [\10\10\10]cd;
print join('', map sprintf("\\%o",ord), split //), $/;
# prints \10\10\10\3\5\7

[download]
__SIG__
use B;
printf "You are here %08x\n", unpack "L!", unpack "P4", pack
  "L!", B::svref_2object(sub{})->OUTSIDE;

[download]

In reply to Inconsistent transliteration for non-printing octets by diotalevi

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